4Ya u're right
Can u post the soln plzzz!!!!!!!!!
Let first line be x = y = z, second line be x=y/2=z/3
and third line is passing through (1, 1, 1).
Area of triangle formed by these three lines is √6 unit, and point of intersection of third line
with second line
is (a, b, c) where a, b, c all are positive, then find the value of a – b + c
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6 Answers
1k
teh 3 cordinates of vertices of triangle will be (a,b,c) (1,1,1) and (0,0,0)
this u got ?
now apply area formula for traingle formed by 3d lines.....u must be knowing it
u get a relation in a b and c
now (a,b,c) lies on 2nd line
so a=b/2=c/3=k
a=k
b=2k
c=3k
put teh values of a b and c in terms of k in the relation found abov
u get a value of k
with it find a b and c and hence a-b+c