About vectors.......

2 Answers

1
metal ·

Let length of vector= r=√(ax2+ay2)
Let θ be the angle with x-axis.
ax=rCosθ
ay=rSinθ
a'x =rCos(θ-α)= r(CosθCosα+SinθSinα)
= axCosα+aySinα
a'y = rSin(θ-α)= r(SinθCosα-CosθSinα)
= ayCosα - axSinα

1
kamalendu ghosh ·

let the initial angle of poinr P be θ....
let r be the dist of point from origin
then in new system
X=rcos(θ-α)
and in the old sys x=rcosθ

similary

Y=rsin(θ-α)

..
y=rsinθ

now substitute the values....

as tanθ=ay/ax

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