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mod (vector a) =a & mod(vector b ) =b ..................then prove that
{(vector a)/a^2 - (vector b)/b^2}^2 = {( vector a - vector b)/ab}^2
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1hey frenz ,,,,,,,,,,,,,,,,,,,,where are u all i need you...........................kal mera test hai...........................
1the sum is quite simple madhu.
{\vec{a}/a2-\vec{b}/b2}2={a/a2-b/b2}.{a/a2-b/b2}
=1/a2+1/b2-2a.b/a2b2
=(a2+b2-2a.b)/a2b2
=(a-b).(a--b)
=(a-b)2/a2b2
1thanx titli...........................kal test hai
& it was puzzling me.............................thankz a lot
