Let the hori vector be A and the other be B.
Then B(y) = P
=> |B|*cos(60) = P
=> |B| = 2P
=> B = -2P*√3/2 i + P j
= - P√3 i + P j
A(x) + B(x) = 0
=> A = A(x) i = P√3 i
So, |A| = P√3 and |B| = 2P
1. There are 2 vectors, one in the horizontal direction and other is inclined at an angle of 600 with the vertical.The resultant is in vertical direction and has magnitude P units.The 2 vectors are:
a)P,2P
b)P,P√3
c)2P,P√3
d)none of these.
Plz show the ans with steps..
Let the hori vector be A and the other be B.
Then B(y) = P
=> |B|*cos(60) = P
=> |B| = 2P
=> B = -2P*√3/2 i + P j
= - P√3 i + P j
A(x) + B(x) = 0
=> A = A(x) i = P√3 i
So, |A| = P√3 and |B| = 2P