we search for the coefficient of x2n in (1+x+x2+......xn)4
.........same thing as above ! what is the other way in this ?
ram has to attempt 4 papers each paper containing maximum 'n' marks
in how many ways he can get a total of 2n marks .....
note:if u want to use multinomial theorem then also provide proof of multinomial thoerem :)
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3 Answers
Lokesh Verma
·2009-12-01 18:01:25
I dont know of a solution outside of multinomial thoerem..
what you will have to do is to look at the coefficient of
x2n in (1+x+x2+...+xn)4
which is same as the coefficient of x2n in (1-xn+1)4(1-x)4
this is a dirty quesiton and if someone has a better proof, i would love to see it
Lokesh Verma
·2009-12-01 18:20:37
btw.. the proof of multinomial theorem i remember is something we had probably discussed sometime back!
Debotosh..
·2009-12-01 18:27:11