5 Answers
tapanmast Vora
·2009-03-23 00:35:52
RAJAT : [lovely solution!!!]
1 doubt : HOW DID U GET ((2^t - 1)/2^t)^r
i.e. in the very first line of ur expression........
Asish Mahapatra
·2009-03-23 04:02:04
tapan see:
if to take (to the power r) common then u have the terms 3/22, 7/23, ... = (2t-1)/2t
see. it is (22-1)/22, (23-1)/23, (24-1)/24 =(15/24)