AIEEE 09 max question

What is the remainder when

82n-(62)2n+1 is divided by 9

I got the answer as 7(just substituted )

Is it rite??

14 Answers

1
Pavithra Ramamoorthy ·

no boss!! i substitued 0 n got ur ans...

then tried substitutin 1 n got 8...

but d ans is 2 :((

1
Philip Calvert ·

ya i got as 2

put n =0 .. hehe [1]
just hoped that it is really correct

62
Lokesh Verma ·

Theoretical solution

(9-1)2n-(63-1)2n+1 is divided by 9

Now can you solve..

1
°ღ•๓яυΠ·

yeah 7 :) put n=0 :D

9
Celestine preetham ·

yes n=2

(63+1)n-(63-1)2n+1 = 63powers + 1 - (-1)2n+1=63β +2

1
gordo ·

thats what happens when u substitute for 'n'...instead of doing that u cud have jus made (9-1)2n - (63-1)2n+1
to get the answer as 2...
it takes lesser tym to do this dan, to luk out for a comfortable 'n'...

1
Philip Calvert ·

com'on u are kidding
n=0 is the best way over here

even idont like all these guessing in maths but at that time it was an advantage

1
°ღ•๓яυΠ·

bt d thing is.......... if 7 is d answer then asnwer can also be 2.....

1
Philip Calvert ·

answer can only be 2 who the heck said it was 7

1
°ღ•๓яυΠ·

if u put n=0 u get answer as 7

39
Dr.House ·

total solutions

http://www.goiit.com/posts/show/995712/aakash_aieee_solutions_content-aieee-2009-solutions-and-analysis-929891.htm

1
Philip Calvert ·

@mruna
l wat kind of n=0 are u putting to get answer as 7 please elaborate as i am utterly unable to understand ur method

11
Anirudh Narayanan ·

THE METHOD OF DIVISION IS NOT THE SAME FOR POSITIVE AND NEGATIVE NUMBERS

SO FOR n=0, U'LL GET -61/9

-63+2/9

-7 + 2/9

sO REMINDER IS 2!!!!

1
rajat sen ·

8\equiv -1(mod9)
so,
8^{2n}\equiv 1(mod9)
62\equiv -1(mod9)
so,
62^{2n+1}\equiv -1(mod9)
so,
8^{2n}-62^{2n+1}\equiv 2(mod9)
so, the answer is 2

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