AITS problem

For a,b,c belonging in R+ the minimum value of (a+3c)/(a+2b+c)+4b/(a+b+2c)-8c/(a+b+3c) A)12+17âˆš2 B)-12+17âˆš2 C)-17+12âˆš2 D)17-12âˆš2.........

6 Answers

http://www.artofproblemsolving.com/Forum/viewtopic.php?t=147142

plz sum 1 post the solution..

cant u get it from link abov

look post 11

i am quitting jee after seeing this question

actaully its a chinese mo prob

dont understand why des guys put such stuff der in the q paper

it wont come in jee in next 100 yrs :P

its not dat tough taking a+2b+c=x a+b+2c=y a+b+3c=z and then by replacing a,b,c in the numerator in terms of x,y,z ds can be solved

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