algebra 2

SHOW THAT IF nâ‰¥6 is composite, then n divides (n-1)! .

1 Answers

write n as p.q such that pâ‰ q (If that cant be done we wll prove seperately!)

lets look at the only non trivial case when the number is a perfect square of a prime...

n=p²

2p<p² since p>2

so (n-1)! is divisible by p and 2p (since they are both less than equal to (n-1)

hence the proof :)

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