Algebra

1) (\a/+\b/)/(a+b) = 5 ????

answer correct hai kya??

Can someone please show the method?.......

Thankyou sir but, alpha + beta + gama + delta = 4

and please show how u've used this inequality

A.M >= G.M

$I am Getting $\prod_{n=2}^{\infty}\frac{n^3-1}{n^3+1}=\frac{2}{7}.

A small hint for the second problem:

\left(n+1 \right)^2-\left(n+1 \right)+1=n^2+n+1

I am not getting \frac{2}{7} btw...

i have got 2/3...by splitting n^3-1 and n^3+1 ,follow the pattern how diagonally terms are getting canceled...by taking limit to infinity we get the solution....may b answer is wrong...but approach is ok..