algebra eqn

solve

1) (x+4)(x+7)(x+8)(x+11) +20=0

2) 2x3+5x2-2x+3=0

13 Answers

23
qwerty ·

for Q 1 hint : 4 + 11 = 7 + 8

if u dont get it then (1) take x+30/4 = t and solve or (2) expand (x+4)(x+11) and (x+7)(x+8) and write x2 + 15x = m,

1
avik ·

thanx solve 2

39
Dr.House ·

the 1st one was discussed in detail here:

http://www.targetiit.com/iit-jee-forum/posts/solve-for-x-12309.html

39
Dr.House ·

areu sure about the 2nd question?

verify once

1
avik ·

yes Q2 corrrect

341
Hari Shankar ·

that cannot be as f(-2) is obviously odd. As a start, from Rational Roots Theorem, check if we have root of the form p/q with p = ±1, or ±3 and q=±1, ±2

update: x=-3 is a root. The other roots are now easily obtained!

1
gauraviscool ·

(12x-1)(6x-1)(4x-1)(4x-1)(3x-1)=5

62
Lokesh Verma ·

this one is not ad difficult either.... Based on same logic as in the first quesiton..

Just think upside down ;) :D

1
avik ·

what is rational roots theorem ?

62
Lokesh Verma ·

if there is a rational root of a plynmilla with integer/ rational coefficients then the root is a factor of last term/ first term...

1
gauraviscool ·

but nishant pleazz help me out wid d sol. of d ques that i posted

62
Lokesh Verma ·

no gaurav.. i confused it with the problem with only 1 4x-1..

I din read properly :P

1
gauraviscool ·

please consider my ques whenever u r free n help me out wid d sol.

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