11How is y≤5? Please explain.
\hspace{-16}$Find all Positive Integer Triplet $\bf{(x,y,z)}$ that satisfy\\\\ $\bf{x!+y!=15\times 2^{z!}}$
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3 Answers
21Very easy..... WLOG x≥y . Hence y≤5.
Easy computation gives no solution for y=5.
If y≤x≤5. we get tiplets:
\boxed{\left(x,y,z \right)=\left(3,4,1 \right)}