This is the only exception....it has minimum at x = 1 whereas maximum at x=-1
i.e. max value = -2
min value = 2
only function as far as i remember that has maxima < minima...
i believe that answer is not given in options....all options are wrong i mean..or did they mean that "positive real number" rather than "real numbers"?
This is the only exception....it has minimum at x = 1 whereas maximum at x=-1
i.e. max value = -2
min value = 2
only function as far as i remember that has maxima < minima...
@sandipan...well i believe that for function f(x)=x+1/x where x= real number...the minimum value tends to -∞ as x tends to -∞!!
we are talking of minimum not local minimum right??ehhhhhh!
Well, It should be -1 ?
@KUNL, What you say me be correct, However If you look closely at the top of the question sheet you'll find something like this:
"Choose the most appropriate among the given 4 options of which only one is correct "
If it's not given then follow this.
Inverse of 2 is 1/2
So the min value of a real number is 1/1 +1/1 i.e 2
D is correct option
What manipal did is correct.
Soham, -2 is a maxima. x+1/x has no minimum value. It only has a local minima at x=1
Kunl, infinities are not real numbers, so this function has no minimum value.