am i wrong...or am i wrong?

i believe that answer is not given in options....all options are wrong i mean..or did they mean that "positive real number" rather than "real numbers"?

8 Answers

11
SANDIPAN CHAKRABORTY ·

This is the only exception....it has minimum at x = 1 whereas maximum at x=-1
i.e. max value = -2
min value = 2

only function as far as i remember that has maxima < minima...

1
kunl ·

@sandipan...well i believe that for function f(x)=x+1/x where x= real number...the minimum value tends to -∞ as x tends to -∞!!

we are talking of minimum not local minimum right??ehhhhhh!

71
Vivek @ Born this Way ·

Well, It should be -1 ?

@KUNL, What you say me be correct, However If you look closely at the top of the question sheet you'll find something like this:

"Choose the most appropriate among the given 4 options of which only one is correct "

If it's not given then follow this.

11
Mani Pal Singh ·

Inverse of 2 is 1/2
So the min value of a real number is 1/1 +1/1 i.e 2
D is correct option

11
Soham Mukherjee ·

Why it is not -2?

71
Vivek @ Born this Way ·

@Manipal..

You mean to say -1/2 is not a Real Number.?

21
Shubhodip ·

What manipal did is correct.
Soham, -2 is a maxima. x+1/x has no minimum value. It only has a local minima at x=1

21
Shubhodip ·

Kunl, infinities are not real numbers, so this function has no minimum value.

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