an easy one in quadratics

A quadratic equation with integral coefficients has two prime numbers as its roots.
If the sum of the coefficients of the equation is prime then the sum of the roots is - ?

Post the method also

7 Answers

62
Lokesh Verma ·

2 and 3 are the roots..

sum is 5

method follows in the next!

62
Lokesh Verma ·

let the quadratic be

p and q be the roots...

a(x-p)(x-q)=0

a has to be + or -1 else it will be divisible by

sum of coeff = a(1-p)(1-q)

we can eliminate -1 case separately..

(1-p) has to be 1 .... or (1-q) has to be :)

also (1-q) to be prime needs 2 as the only possible value.. cos all other primes -1 is an even number which is greater than 2!

1
Rohan Ghosh ·

ya i followed the same method ...
one of my friends gave amethod involving cases ..
i wanted to see what you adopt to bhaiyya.

1
Rohan Ghosh ·

this was an objective problem from last year's AITS series

62
Lokesh Verma ·

okie.. gr8 :)

1
nshekhawat shekhawat ·

samaj nai aya
hw u eliminate it

62
Lokesh Verma ·

may be i used the wrong phrase.. you could say deal that case separately...

It is basically similar.. if not the same!

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