241/1!.9! +1/1!9! +1/3!7!+1/3!7! +1/5!5!
now multiply by 10! both sides
=>10C1 +10C3+10C5+10C7+10C9=2m10!/n!
=>210-1/10!=2m/n!
Given : 21!9! + 23!7!+ 15!5! = 2mn!
Find the orthocentre of the Δ with sides x-y+1=0, x+y+3=0 and 2x+5y-2=0 in terms of m and n.
Very Good Question....Try it... :-)
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11 Answers
39eureka , anyone can commen. have some work to support what u said...
24
1Eurie...one small error...it will be 10! rather than just 10... :-)
24i have corrected that aveek
now
slope1=1,slope2=-1
=>perpendicular lines
=>orthocentre at intersection
=>P=(-2,-1)
fro mthe realtion we get m=9 ,n=10
=> orthocentre=(2m-2n,m-n)
24b555...dont challenge me in those things I am damn sure.......I never write comments uselessly...unless i get mad .....
i hope u r not taking my comments seriuosly dude...[1]
i was just blabbering in this post
1divide and multiply by 10!
u will get m=9 and n=10
now i think u can get orthocentre as (-50/3,-25/3)
i.e (-15n/m , -15n/2m )ans