ANKIT Ques 1 ... simple ..

asish i think u have also done a calc .. error !! [50]

Sry, thats supposed to be 3²+2²+1²

The thing is, if you know the inequality, using these constants will follow immediately. For JEE dont bother about this inequality.

@manipal: chote bhai, just look up Cauchy Schwarz Inequality in wikipedia

waise, this will not come in jee or aieee etc. so dont bother about it right now

humlog baki sab ko doob marna chahiye .. chale hai iit clear karne .. aur yeh simple sum nahi bana ... [186]

prophet .. jiyo yaar .. brilliant ..

you asked for values of a,b and c. So i thought you might like to confirm whether thats right or wrong.

In any case, by Cauchy Schwarz Inequality, we have

(3^2+2^1+1^2)(a^2+b^2+c^2) \ge (3a+2b+c)^2 = 49 \Rightarrow a^2+b^2+c^2 \ge \frac{49}{14}

Hence 100 (a^2+b^2+c^2) \ge \frac{49}{14} \times 100 = 350

Equality occurs when \frac{a}{3} = \frac{b}{2} = \frac{c}{1} using which you get the values given.

prophet any logic to support ur answer ....

very easy question .. but of iit 4th year level

(this was just a bad joke .. this question is very well there in our syllabus ...) ..

guys dont give final value .. give a,b,c ....

Ankit : UR a is crrct, but b and c are wrong......

I got a much leser value than wat u got.....

BTW IS MA ANS. CRRCT????

soln .. don't see before u try ...

minimum value for the eq.. a² + b² + c² is when a = b = c or
3a + 2b + c = 7 .. or 6a = 7 .. a = 7/6
100(3 (7/6)²) = 408.33

there are 100% chance of my soln. being wrong .. because by hit and trial a = 4/3 , b = 1 , c = 1 i got value as 377.77

a,b,c can take all real values ...

[50]
[50]

72.309 .. tapan how did u get this result ...

SOMETIMES LOGIC RULES OVER THE STANDARDS METHODS

MY LOGIC a²+b²+c² is always going to be positive

SO U WONT GET ANY PROFIT BY TAKING A NEGATIVE NUMBER

SO THIS WOULD HAVE MIN WHEN

a=1 b=2 c=0
a=2 b=0 c=1
so i think it should be 500
please confirm it