Answer is (2) b3 + ac(a+c) = 3abc
If one root of the equation ax2+bx+c=0 be the square of the other root, then....
i) a3+bc(b+c)=3abc
ii)b3+ac(a+c)=3abc
iii)c3+ab(a+b)=3abc
iv) none of these....
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4 Answers
prateek punj
·2009-04-28 09:36:50
plzzzz solution.....
i think i messed this up in calculatory part.....