1i was right i messed it up in calculations....thnx...again....
If one root of the equation ax2+bx+c=0 be the square of the other root, then....
i) a3+bc(b+c)=3abc
ii)b3+ac(a+c)=3abc
iii)c3+ab(a+b)=3abc
iv) none of these....
-
UP 0 DOWN 0 0 4
4 Answers
1plzzzz solution.....
i think i messed this up in calculatory part.....