the AP will be - 101 , 104, 107, ...... 998
common diff. = 3
first term=101
last term = 998
no. of terms = 300
total sum = 300/2 * (101 +998 ) =164580
What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 3?
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2 Answers
Aditya Bhutra
·2011-08-29 09:18:45