1Seems the XI people have run out of adrenaline :)
I am starting this series of question specially for students who are in class XI and have just started preparing... If you are in a higher class (Read XII/ Passout) please hold ur adrenaline rush and give chance to the beginners....
\frac{\sqrt x++1/\sqrt x-\sqrt2}{\sqrt x+1/\sqrt x}=\frac{\sqrt x+1/\sqrt x}{\sqrt x+1/\sqrt x+3\sqrt2}
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8 Answers
36the quesstion isnnt clear...
please write it correctly....
hving confusion wth the terms...
49the question is:
Solve for x:
\frac{\sqrt{x}+\frac{1}{\sqrt{x}}-\sqrt{2}}{\sqrt{x}+\frac{1}{\sqrt{x}}}=\frac{\sqrt{x}+\frac{1}{\sqrt{x}}}{\sqrt{x}+\frac{1}{\sqrt{x}}+3\sqrt{2}}
21Replace \sqrt{x}+\frac{1}{\sqrt{x}} by a
The equation becomes \frac{a-\sqrt{2}}{a}= \frac{a}{a+ 3\sqrt{2}}
Simplifying and rearranging a = \frac{6}{2\sqrt{2}} = \frac{3}{\sqrt{2}}
So, \sqrt{x}+\frac{1}{\sqrt{x}} = \frac{3}{\sqrt{2}}
Solving the quadratic for \sqrt{x} we get , \sqrt{x} = \frac{\frac{3}{\sqrt{2}}\pm \sqrt{\frac{17}{2}}}{2}
Squaring it, we get the value of x
7THe qus was too easy @NISHANT sir..
Even a class 9 student can do it, leave alone 11.what was there in dis qs?
will it ever come in RMO?...lol...