Binomial..Akshant's Challenge>>

BITSAT 2015 Papers › Algebra questions › Binomial..Akshant's Challenge>>

(n!)! is divisible by

A--28(2n-1)^n-1
B--(3n)!
C--(n!)^n!
D--(n!)^(n-1)!

#Mathematics #Algebra

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7 Answers

1

Rocky Crazy ·2009-10-14 11:39:15

Post the solution complete!!If u can!!

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1

Rocky Crazy ·2009-10-15 05:23:11

Ny here??

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39

Dr.House ·2009-10-15 05:32:25

put n=3

d is the answer

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1

Rocky Crazy ·2009-10-15 05:36:06

Thts shortcut dude..I want to solve it complete..algebrically..i mean in subjective kind of approach..

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39

Dr.House ·2009-10-15 05:39:39

not that i couldnt do it...

lets others try .. its a good exercise

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1

Rocky Crazy ·2009-10-15 05:44:44

Yup..Nyways thanks for ur try..

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1

akash93 ·2009-10-15 07:44:10

just use the fact tht the product r consecutive int is div by r!
1,2,3...n
n+1,n+2..
2n+1.

n!-n,..n!
total there r n-1! grps of n consecutive int
the product is div by n!^n-1!

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Your Answer

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