Binomial

JEE Advanced 2015 Preparation › Algebra questions › Binomial

If 7^103 is divided by 25,Then find the remainder?

#Mathematics #Algebra

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7 Answers

1357

Manish Shankar ·2009-10-02 23:59:01

7^103=7.(7²)⁵¹=7.(50-1)⁵¹

this may help

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Rocky Crazy ·2009-10-10 11:28:24

Yeah bhaiya i tried the same way..Bt i m getting 7 as answer bt answer given is 18..Kindly tell me how to proceed further..

Thanks fr ur reply..

Frnds u can also help..please..if can solve..

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msp ·2009-10-10 11:40:24

7²â‰¡(-1)mod(25)

7¹⁰²â‰¡-1mod(25)

7=-18mod(25)

7¹⁰³=18mod(25)

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Rocky Crazy ·2009-10-10 12:14:00

Whts dat??Cant we use binomial??Nyways thanks fr ur try...

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$ourav @@@ -- WILL Never give ·2009-10-10 18:52:27

msp has done using congruences....check out congruences in fundamentals in forum...n msp has done exactly correct

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msp ·2009-10-10 19:50:35

dude the given no is 25(K)-7 (EXPAND BY BINOMIAL)

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Rocky Crazy ·2009-10-10 22:11:47

Thanks alot!!

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω