binomial theorem

pls answer

2 Answers

106
Asish Mahapatra ·

the series is basically e^{1+x+x^2}

e^{1+x+x^2} = e.e^{x}.e^{x^2}

e^{1+x+x^2} = e.(1+x+x^{2}/2! + x^{3}/3! + x^{4}/4!+..)(1+x^{2} + x^{4}/2! + ..)

So coefficient of x4 = e.(1*1/2! + 1/2!*1 + 1/4!)

= \frac{25e}{24}

1
kunl ·

this one won't come in jee rest assured[1]
power series is not in syllabus!

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