Birthday Problem!!!

In a group of n people, what is the probability that at least 2 people have the same birthday?

2 Answers

no one having the same birthday =

365.364.... (366-n)

now of ways to have the birthday = 365^n

if n<=365

then it is 365.364.... (366-n)/365^n
else it is zero..

ofcourse i am not considering fractions and leap years...

**edit**
Answer wil be 1- answer above!

Great bhaiyya!!!!!!!!!!!!!

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