ccomplex nos

wen u urself r having doubt , then how do u expect others to undersatnd it ??

sorry but pls dun mind,,,, i din understand ur soln either.

Isnt'it??
I did not use any complex thing .....
instead of keeping e^iθ

i mean to say that the value of e^iθ in this case is1
thats it
and more over the problems on complex numbers should be done in a complex way!!!
haha!!

but its given ! dat both of them are equal!

yaar y are u making this so complex...

woh asaan sa .. bachcha type method din work or wat ?

(my first post..)

dat din work ??

well , what u r trying is possibily this x + 1/x = 2 . which is true iff x=1 . but here it's 2.e^iθ . I don't think that approach works here. that becomes a particular case I think.

I just doubt because there are some conceptual errors...
in the problem itself...
so I am asking for open discussion.......
just we have to use some logic for this question
just brood over the soln what I gaVE

because the maximum value ofmod cosθ+isinθis 1
because it is cos2θ naaaa
so
since it is equal θshould be either0 or pi......

am I correct??
I am having doubt in my soln

y u took minimum suddenly ?

I got it
there is nothing to do with the eqn
the min value of x+1/x=2
so 2(cisθ) sholud be min so θshould be 0.......
so α+β=2
αβ=1
.........carry on.....

I dont know about the soln!! I am trying but one step what sky gave is wrong
sum of the roots is 2eⁱ⁰

α+β = 2 . e^iθ no ?

z² + 1 = 2z e^iθ

=> z² + 1 - 2z e^iθ = 0

now,

α+β = 2 e^iθ (edited)

αβ= 1

try with this...