hint:
find all 3 termed AP`s with sum of those 3 terms equal to 15 and that should get u going
maximum no. of ways of distributing 15 distinct objects to three persons such that..the no. of objects received by the persons are in A.P.
Ans(15)! / (5!)3
hint:
find all 3 termed AP`s with sum of those 3 terms equal to 15 and that should get u going
One person gets exactly 5..
The others get the remaining..
15C5x210x3 - 2x15C5x10C5
Dont know if it matches ur answer.. i am in a hurry... so you check this yourself...