numerator is 2n+1 +2n-1 +√(2n-1)(2n+1)
now we will try
a2 +b2 +ab /a+b
i guess it is done
multiply divide by a-b
u will get a3 -b3
now employ method of difference
let an be a sequence defined on positive integers by setting a_{n}=\frac{4n+\sqrt{4n^{2}-1}}{\sqrt{2n+1}+\sqrt{2n-1}}
then find the value of a_{1}+a_{2}+a_{3}+a_{4}+..............a_{60}
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2 Answers
akari
·2009-12-21 05:30:47