39answer is not 64 and answer is not 204
an 8 x 8 array consists of the numbers 1,2,3,.............,64 . consecutive numbers are adjacent along a row or coloumn.
what is the minimum value of sum of numbers along a diagonal ?
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19 Answers
39HONEY,
u see after 13 follow the line that gies to the left of it and put consecutive numbers in each box.
like after 13 , put 14, then 15 , then 16 ,. so on........ (all these should be put on the blocks that lie on the line)
39suppose let us assume it is possible to improve upon the arrangement i showed above.
clearly the diagonal in this question should contain odd numbers,and the largest would have to be atmost 37,once this number is put down , we must remain on the same side of the diagonal.
there are exactly 16 black squares and 12 white squares on each side.
hence the largest number is 37 and only one square on the largely empty side of the diagoal has been filled.
however, there are 13 odd numbers from 38 to 64 , but we atmost 12 white squares to accomodate them.
SO IMPROVING UPON 88 IS IMPOSSIBLE.
1hey b555 anuj is correct..........if we consider the diagonal elements......
then it will come in this order.........da
1,10,19,28,37,46,55,64........so we form an AP here...........with 9 as common difference and starting integer 1...........
the sum of the AP
= common difference /2(1st term + final term)
= 8/2 (1+64)
= 4 X 65
= 260
Hope u got it!!!!!!!!!
1an 8 x 8 array consists of the numbers 1,2,3,.............,64 . consecutive numbers are adjacent along a row or coloumn.
so hw cld be consecutive no's written without repetition?
39read the question.
an 8x8 arrya consists of numbers 1,2,3,4,.......,64.
so show me those numbers on your board.
i dono much better english than that.
i could only infer thaat we have all 64 numbers on the board.
39ya. but honey u have to arrange al 1 to 64 satisfying the given condition.
i knew most would make this mistake.
try try. no repeatition is allowed
1consecutive numbers are adjacent along a row or coloumn.
itz given in the ques
39come on , how do u guys arrange these numbers huh? all 1to 64 have to be arranged!!!!!!!!!!!!!!!!
1
we are starting from 1 coz we need min sum
thn adding no.'s on diagonals as
1+3+5+7+9+11+13+15=64
39anuj i dont think u understood the question.
and nishant sir and abhishek , can u say how u got the answer? i didnt get how u got 64
