If the complex sequence of numbers z0, z1, z2........satisfy z_0=i+\frac{1}{137} and for n≥1 z_{n+1}=\frac{z_n+i}{z_n-i}
then find the value of z2007
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2 Answers
Hari Shankar
·2010-09-04 02:02:41
Let z_n = ix_n
Then the sequence satisfies x_{n+1} = \frac{x_n+1}{x_n-1} which is easy to see satisfies x_{n+2} = x_n
From this it is easy to see that z2007=z1 which can be easily computed