Complex nos.........

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this is really a simple one...... just wanted to check my answer. So pls co-operate [1]
Using transformations or otherwise , find correct four places of decimals the value \prod_{1}^{5}{}(z_i+1)/(2z_i-1)
where Z_i are the roots of z⁵=1.
I got 0.0645.........so pls check . I dont have solution for this [7]

#Mathematics #Algebra

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1 Answers

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sindhu br ·2009-05-11 08:26:12

let w=(z_i+1)/(2z_i-1)
z=(w+1)/(2w-1)

((w+1)/(2w-1))⁵=1
(2w-1)⁵-(w+1)⁵=0
\prod_{1}^{5}{}(z_i+1)/(2z_i-1)=2/31=0.0645

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