71
* Slight mistake in denominator of Expression (1).
Q) let a,b,c be distinct complex nos. such that |a|=|b|=|c|>0 .
if a+bc , b+ac , c+ab are real numbers then abc = __
Ans.1
a method or a solution would be appreciated.
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3 Answers
262nice solution vivek ,
just want to point out that the condition
a+bc = b+ac = c+ab = 0
is not possible since a,b,c are distinct
1@vivek you should have directly given this link http://www.artofproblemsolving.com/Forum/viewtopic.php?f=151&t=473251
would have saved you a lot of time.