complex numbers

find the solution set for z given that,

|z+a| + |z-a| = |a|

where a = real number

2 Answers

106

Asish Mahapatra ·2010-12-29 06:27:20

|z+a| + |z-a| â‰¥ |z+a - (z-a)|
= |2a|

So, there doesnt exist any z for which abv eqn gives a soln

thanks ashish
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