complex numbers

iZ³+Z²-Z+i=0 then show that |Z|=1
plz tell me a shortcut for this problem........................

1 Answers

z=i satisfies it
=>eqn reduces to (z-i)(iz²-1)=0=>(z-i)=0 or (iz²-1)=0
take modulus and get the answer

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

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