Nice meths Viv,
btu guyz in caase u cant find ne such methd, always remember to take β=i, α = 2i
such substituitions r always hady and time-savvy
If α,β are different complex nos. with \left|\beta \right|=1 then find \left|\frac{\beta -\alpha }{1-\bar{\alpha }\beta}\right|
1
divide and multiply the numerator by \beta , you will now get the expression in the form \left| \frac{z}{\bar{z}}\right| = 1
Nice meths Viv,
btu guyz in caase u cant find ne such methd, always remember to take β=i, α = 2i
such substituitions r always hady and time-savvy
He took just 4 the sake of answer
take 1+i/2,3i,8i,√2i
anything u wish
this should hold 4 everything [1]
i asked that becoz nothing was mentioned about α (neither magnitude nor argument)......
so it means we have the freedom to take anything
IF we have to do the question by that way
the actual answer lies in #2
ya ofcourse vivek's approach is the best....but tapans method is best for exam..[3][3][3]