Complex numbers

If 'a' is a complex number such that |a|=1.Find the values of a,so that equation az2+z+1=0 has one purely imaginary root.

2 Answers

2305
Shaswata Roy ·

Let

a=x+iy,z=mi

Substitute these values in the equation.

(xm2+1)+i(m2y+m)=0

x=y2

a=1
x2+y2=1
x2+x1=0
x=21±5

x>0 since y has to be real.

x=251y=251

341
Hari Shankar ·

http://goiit.com/posts/list/algebra-help-needed-in-a-question-of-complex-numbers-1199242.htm

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