If 'a' is a complex number such that |a|=1.Find the values of a,so that equation az2+z+1=0 has one purely imaginary root.
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2 Answers
Shaswata Roy
·Oct 13 '13 at 23:02
Let
a=x+iy,z=mi
Substitute these values in the equation.
(−xm2+1)+i(−m2y+m)=0
→x=y2
∣a∣=1
→x2+y2=1
→x2+x−1=0
→x=2−1±√5
x>0 since y has to be real.
x=2√5−1y=√2√5−1
Manish Shankar good work :)
Upvote·0· Reply ·Oct 17 '13 at 22:11
Hari Shankar
·Oct 12 '13 at 22:46
http://goiit.com/posts/list/algebra-help-needed-in-a-question-of-complex-numbers-1199242.htm