106ez = 0
for no value i think
Q1 FInd number of values of z for which ez=0
Q2 Number of values of z for which sinz=0
Q3 Number of values of z for which cosz=0
Q4 What is solution set of sin(iy)=0
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9 Answers
106sinz=0 ==> for sin to be defined z must be purely real and it is z=npi
106cosz=0 ==> again z is purely real and is equal to (2n+1)pi/2
106sin(iy) = 0 for sin function to be defined .. iy must be purely real
==> y is purely imaginary let = ix
So. it is sin(-x)=0
==> x=npi
==> y=i*npi
1fr second one it must be purely img ... isnt it???????? u r wron it seems......
106arey sin function is defined for real numbers only.. what is the domain of sin function? thats why...
1k.. k..k..
srry.................
was jus thinkin it blindly.......
