(1-x)^p/q=1-p/1![x/q]+p/2![x/q]2-p/3![x/q]3+......
express (2^(1/3)-1)^(1/3)
in the form of a,b,c (use only + or - btw a,b,c)
where
a= (1/9)^ (1/3),
b= (2/9)^ (1/3),
c= (4/9)^ (1/3)
-
UP 0 DOWN 0 0 2
express (2^(1/3)-1)^(1/3)
in the form of a,b,c (use only + or - btw a,b,c)
where
a= (1/9)^ (1/3),
b= (2/9)^ (1/3),
c= (4/9)^ (1/3)