b)2(15!)(16!)(17!)
Take 15! common from 1st row,16! common from 2nd row and 17! common from 3rd row and then proceed..
The value of the determinant
is
(a) 15!+16! (b) 2(15!)(16!)(17!) (c) 15!+16!+17! (d) 16!+17!
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2 Answers
Anurag Ghosh
·2014-04-01 23:05:47
Soumak Roy
·2014-04-05 08:57:45
But anurag, if we take 15!, 16! and 17! common, then after doing row and column operations, isnt the determinant coming to be zero ?
- Dwijaraj Paul Chowdhury No...I guess after taking 15! in common you got 1, 16 and 17 in the row/column...i made a similar mistake first..it should be 17*16 ,16 and 1
and same for all other cases as wellUpvote·0· Reply ·2014-04-07 21:46:26
- Soumak Roy ya dwijaraj ... same mistake !!