First one is based on simple reasoning, you can try it yourself. (If you haven't dumped ur homework herein)
1. If a,b,c are odd integers , ax^2+bx+c=0 cannot have ratioal roots. Prove it.
2. For what values of a does the eqn (2a+1)x^2-a(x-1)=2 has one root greater than 1 and other less than 1.
3. If a and b are the roots of x^2+px+q=0 the express a5+b5 in terms of p and q.
4. Solve xy=yx and x2=y3.
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3 Answers
Shubhodip
·2010-12-10 01:36:27
4) take log both sides..
3) a5 + b5 = (a2 + b2 ) (a3 +b3 ) -a2b2 (a+b)
2)is the answer (-0.5,0.5) ?
Vivek @ Born this Way
·2010-12-10 02:44:25