easy limits

\lim_{n\rightarrow \infty }(\left(n^{2}-n^{3})^{1/3}+n \right)

not my doubt......found it gud

6 Answers

nope

sry sry sry a small mistake

The same logic works .. doesn;t it ;)

yes bhaiya.....nearly same thing.....and ya xyz its 1/3

ur limit is :
n(1-(1-1/n)^1/3)
expanding the underlined expression using newton's binomial theorem we get the answer?
wats ur approach?

well i had a diff method

use of this formula

a+b=a³+b³a²-ab+b² somwhere :P

lim nâ†’âˆž (n.(1n-1)^1/3 +n)

lim nâ†’âˆž n( (1n -1)^1/3 + 1^1/3)

now apply this formula

a+b=a³+b³a²-ab+b²

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