EASY ONE.....

\frac{4}{19}+\frac{44}{19^{2}}+\frac{444}{19^{3}}+......infinity

15 Answers

1
prateek punj ·

please give the answer of this....

1
vector ·

trying wait a minute

1
vector ·

76/135 (may be wrong in calculations)

1
MATRIX ·

4/19.............

1
MATRIX ·

[77]...........

1
vector ·

how cud 4/19+ sumthing be 4/19

1
prateek punj ·

options....

a)16/35

b)38/81

c)36/171

d)none....

i got (b)...but the ans is (c)...given.....

1
vector ·

temme how u did

9
Celestine preetham ·

gvn =4 (1/19 + 11/192....)

= 4(1+10/19+100/192....)(1/19 +1/192...)

=4X19/9/18 =38/81

me too gettin b !!!!!!!

1
prateek punj ·

first take 4 common....then multiply & divide by 9....then write...

9=10-1

99=102-1

999=103-1...

then forming two g.p.

\frac{4}{9}\left[\left(\frac{10}{19}+\frac{10^{2}}{19^{2}}+... \right)-\left(\frac{1}{19}+\frac{1}{19^{2}}+..... \right) \right]

1
prateek punj ·

okkkaaaa i just wanna confirm this only....thnx....

1
vector ·

ya its b only i got ma calculation mistake

1
gordo ·

write down the individual term...resolve into 2 GPs...add them up to get the answer as B)
cheers!!

1
MATRIX ·

hm..........my head not workin ...........

1
MATRIX ·

[101].........

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