Equation...........

$To solve the equation:\\\\ $\mathbf{2^{2x+2}-\frac{1}{2}.2^{x^2}+2x=x^2-3}$\\\\ Ans::\Leftrightarrow$\mathbf{x=3,x=-1}$

1 Answers

it can be simplified to

2^2x+2 - 2^x²-1 = (x-1)²-4

for x>3 or for x<-1 , LHS is negative whereas RHS is positive

so x Îµ [-1,3]

for x Îµ (-1,3) LHS is positive whereas RHS is negative

so at x = -1 and 3, LHS = RHS =0

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