1no..i was asking about quartic equation....(x^4)..a equation having four roots???..how to find its factors??
8 Answers
1357Are you asking about quadratic equation??
ax2+bx+c=0
multiply whole with a
a2x2+abx+ac=0
(ax)2+2.(ax).(b/2)+ac=0
add b2/4 on both sides
(ax)2+2.(ax).(b/2)+ac+b2/4=b2/4
(ax)2+2.(ax).(b/2)+b2/4+ac=b2/4
(ax+b/2)2+ac=b2/4
(ax+b/2)2=b2/4-ac=(b2-4ac)/4
(ax+b/2)=±√[(b2-4ac)/4]
ax+b/2=±√(b2-4ac)2
ax=-b/2±√(b2-4ac)2
x==-b±√(b2-4ac)2a
11357I don't think you need to know the factorization of four degree polynomials
If the polynomials are simple, you can try hit and trial method
otherwise it is not required
1like can you show me an example of the hit and trial method??..do u mean the vanishing method that is used to find the factors of a cubic equations?
62Indrajit for instance let us look at
4x5+3x3+6x2+x+4=0
What could a root of this one be?
62sorry Indrajeet..
I missed this one..
see by observation
is -1 a root of this one?