1but that is not a fool proof method
if 1>=a>=b>=c>=0 & λ is a real root of the equation x3+ax2+bx+c =0 then max. value of modulus λ is ?
a)1
b)1.5
c)2
d)0.5
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3 Answers
1The answer is 1.............
i took a=b=c=1.....as an example.....
so the eqn became x3+x2+x+1=0
=(x2+1)(x+1)=0
so λ=-1..........so modulus of it is 1.......[3][3]...
i dint find a suitable method for it hehe
1this one is nice .........
objective ke liye akand u are right......
but ....... [12]