24Nishant sir has almost done it
[2007!(2008.2009-1/2007)2007!(2009)]
=>[(2008.2009-1/2007)2009]
=>[2008-12007.2009]
12007.2009<1
=>2008-12007.2009<2008
=>[2008-12007.2009]=2007
(1)The value of [(2009!+2006!) /(2008!+2007!)]
here [.] denote greatest integer function.
ans: (a) 2009
(b) 2008
(c) 2007
(d) 1
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2 Answers
62This one is not very difficult i guess...
first of all note that the denominoator is 2007!(2009)
the numerator is 2007!(2008x2009-1/2007)
Now can you solve it?
the answer will be 2007 :)
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