1Hey just do the middle-term-factorisation method !
2m'2 - mm' -m2
= 2m'2 - 2mm' + mm' - m2
= 2m'(m'-m) + m(m'-m)
= (2m' + m)(m'-m)
Guess that's it. :)
plz factorise tis one for me
2m'2 - mm' - m2
okay i know the ans...bt plz do d steps fr me..
thanks in advance!!!
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5 Answers
1
62there are 2 options either to solve the quadratic in m' or to try to express it as the difference of perfect squares..
2m'2-2.(√2m')(1/2√2m)+m2/8 - 9m2/8
= (√2m'-m/2√2)2-(3/2√2m)2
Which can be further factorized..
1@ Nishant Sir :
I have a slight confusion about this type of factorisation.....
I was given this type of a sum, but the maths teacher said that I CANNOT use the quadratic formula to solve it...
Why ? :-|
62I dont know why he said that
i would have done this..
let m'=y
so the equation is 2y2-xy-x2
when we put x=y we get a zero..
so y-x is a factor of this we can find the other factor...
I guess you need to give some basic maths lessons to your sir ;)