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If high voltage (440V) current is applied on the field which is given by the graph y-mod(y)-x+mod(x)=0.Then on which of the following curve Mr.Faraday can move so that he remains safe.
a)y=e-mod(X) b)y=1/x
c)y=signum(x) d)y=-mod (m+mod(x)) (m >3)
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11 Answers
11y-lyl=x-lxl
in I quad,
y-y=x-x
0=0?????
[12]The whole of I quad satisfies this.[7]
In II Quad,
y-y=x+x
x=0
[12] only +y axis
In III Quad,
y=x
In IV Quad,
y=0
[7][7][7][7][7][7][7][7][7][7]
3
62y-mod(y)-x+mod(x)=0
so y+|y|=x+|x|
if x>0, y>0
then it is x=y
when x<=0, y>=0, then y=0
when x>=0, y<=0, then x=0
when x<0, y<0, then any point axis...
The option d is the only one which goes with the one given above and is equipotential .. bcos the line parallel to the x axis and in the 4th quadrant will be equipotential
1Wrong question,question is on which of the curves can Mr Calculus move to remain safe
62yup i did x+|x| ramkumar and ani..
I dont know why.. but i am getting none of these! :(