1What is the conclusion of the above solution?
find coefficient of x49 in expansion of (x+1)(x+2)(x+3)......(x+99)
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2 Answers
62Divide by x49 to get
coefficient of 1 in
(1+1/x)(x+99) (1+2/x)(x+98) (1+3/x)(x+97) ............... (1+49/x)(x+51) (x+50)
(x+100+99/x) (x+100 + 2.98/x) (x+100+3.97/x) .... (x+100+49.51/x) (x+50)
Which is the same as 10049.50 + coeff of 1/x in (x+100+99/x) (x+100 + 2.98/x) (x+100+3.97/x) .... (x+100+49.51/x)
which i can tthink of an easy way to figure out :(
