You should give full problem
sin-1{x2 + 1} 2x
because if this Equation equal zero than
Sin-1{x2+1}/2x= 0
{x2+1}/2x=0
x2+1=0
x2=-1
X=√-1
http://math.tutorvista.com/geometry/adjacent-angles.html
find domain of sin-1{x2 + 12x} m not able to find it... please help me...!!
i m not sure but i think its domain consists of two points -1 & 1
You should give full problem
sin-1{x2 + 1} 2x
because if this Equation equal zero than
Sin-1{x2+1}/2x= 0
{x2+1}/2x=0
x2+1=0
x2=-1
X=√-1
http://math.tutorvista.com/geometry/adjacent-angles.html
(x2+1)/2x=(1/2)*(x+1/x)
So we have
(1/2)*(x+1/x)≤-1
(1/2)*(x+1/x)≥+1