find f(x)

A differentiable function satisfies f'(x)=f(x)+2ex with initial conditions f(0) =0. The area enclosed by f(x) and the x axis is____

12 Answers

3
msp ·

I THOT DAT SOMETHING IS MISSING PLEASE REPLY

1
Aneesh Gupta ·

is it infinite?

33
Abhishek Priyam ·

first order diff eqn naa...

33
Abhishek Priyam ·

dy/dx-y=2ex

d(exy)/dx=2e2x

exy=e2x+c

f(0)=0..

e0(o)=e2*0+c
c=-1

therefore f(x)=e2x-1
ex

Now...

33
Abhishek Priyam ·

Area is infinite...

:)

3
msp ·

yes abhi i have also got the same eqn .tx for ur reply da

i asked only to confirm

3
msp ·

sry da if u find waste of time

33
Abhishek Priyam ·

no problemo..... :)

1
pankaj sachan ·

area between f(x) and -ve x axix will be finite and equal to 1

y = 2xex

3
msp ·

how did u got the function sir can u give me the soln

1
pankaj sachan ·

f'(x) = f(x) + 2ex

f'(x) - f(x) = 2ex

f'(x)e-x - f(x)e-x = 2

d/dx(f(x)e-x) = 2

rest is simple

3
msp ·

tx sir

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