1put x-3 =10cosθ
and y-4=10sinθ
as then it becomes a parametric form of circle as given in equation
parameter =θ
hence x+y =7+10(sinθ+cosθ)
hence ans =
min =7-10√2
max=7+10√2
find minimum and maximum value of x^2+y^2
if (x-3)^2+(y-4)^2=10^2
-
UP 0 DOWN 0 0 9
9 Answers
11@rohan2007
Can you please explain,on what basis,you substitute x-3=10sinθ and
y-3=10cosθ
1it follows form the parametric equation of the circle
(x-a)2+(y-b)2=r2
each point can be expressed of the form
(a+rcosθ,b+rsinθ)
hence above i have written x and y in that form..
1it is due to parametric form of any st. line passing through center 3,4 and having a slope tanθ cutting circle at x,y. find distance of x,y from origin.
1hey rohan we are asked to find the value of x^2 + y^2 not x+y
the answer is 169 and 25
there is a simple logic
we hve to find the distance of the points nearest and closest to origin
so find the equation of the diameter passing through origin and find the pts. of intersection
1hence x+y =7+10(sinθ+cosθ)
here rohan made a mistake
it was x^2+y^2
i realised now only..
btw.. good solution coolspirits :) that was awesome :)
1swetha did you change the ques now
as i saw it find the min. and max value of x+y
62No rohan if she did.. there wud have been a small thing written under her post : "Last edited on:......."
neways dont worry ur approach was right.. :)